parlay possibilities

**hyudra** · 11-24-11, 12:37 AM

10 nCr 5 = 252

**rfr3sh** · 11-24-11, 12:49 AM

^^ is correct

my answer was based on my misreading of the OP's question

**LVBOUND** · 11-24-11, 09:31 AM

Are you guys sure this is correct?

I think this is correct as far as combinations in order.

For example for 6 teams the total ways to play a 5 team parlay are 5 right?

**LVBOUND** · 11-24-11, 10:25 AM

Bump please, where all the smart guys at.

**LVBOUND** · 11-24-11, 12:32 PM

Sooooooo?

**phillysfinest4** · 11-24-11, 01:10 PM

3 teams is 6 combos (3*2*1)
4 teams is 24 combos (4*3*2*1)
Etc, make sense?

**FindTheLock** · 11-24-11, 01:19 PM

unless you're trying to calculate the options for totals too.

**FourLengthsClear** · 11-24-11, 01:19 PM

I think others have (possibly) misread your question. By a pool of 10 teams, I assume you mean 5 matchups and you want you cover all possibilities from those 5 matchups, is this right?

If so it is simply 2^5 = 32 combinations

**LVBOUND** · 11-24-11, 01:24 PM

Yeah if I had a pool of 10 teams and wanted to make as many parlays as possible so that if any of 5 teams won I would win at least 1 parlay.

**rfr3sh** · 11-24-11, 01:27 PM

But are the 10 teams all from different games

**LVBOUND** · 11-24-11, 01:29 PM

Yes the idea behind this was to parlay underdogs from 10 games. In sets of 5

**rfr3sh** · 11-24-11, 01:31 PM

Pretty sure its 252 but whatever you are thinking wont work

**FindTheLock** · 11-24-11, 01:33 PM

I think what he is meaning to say is that he would like to know the total possible number of different outcomes that can occur when 5 matches are played with each match containing 2 teams equating to a possibility of 2 outcomes in each individual one. No draws or totals.

**FourLengthsClear** · 11-24-11, 01:33 PM

Originally posted by LVBOUND

Yes the idea behind this was to parlay underdogs from 10 games. In sets of 5

Then the answer given earlier by Hyundra is correct (252).

**LVBOUND** · 11-24-11, 01:40 PM

Crazy that seems high, buy very possible.

The idea was to take the 10 highest MLB dogs or nhl dogs and parlay them in sets of 5 each at 10 each parlay.

They pay around 2800-4000 each.

From the rough research I did 5 of 10 won at least half the time. With some days 7 winning. This would cause 2 parlays to win.

Nothing serious was just brainstorming.

**FourLengthsClear** · 11-24-11, 02:07 PM

Originally posted by LVBOUND

Crazy that seems high, buy very possible.

The idea was to take the 10 highest MLB dogs or nhl dogs and parlay them in sets of 5 each at 10 each parlay.

They pay around 2800-4000 each.

From the rough research I did 5 of 10 won at least half the time. With some days 7 winning. This would cause 2 parlays to win.

Nothing serious was just brainstorming.

If you had 5 out of the 10 winning - you would have 1 winning 5-team parlay
If you had 6 out of the 10 winning - you would have 6 winning 5-team parlays
If you had 7 out of the 10 winning - you would have 21 winning 5-team parlays

**phillysfinest4** · 11-24-11, 02:35 PM

Yeah I was thinking of exotics betting at the track

**LVBOUND** · 11-24-11, 02:36 PM

Thanks as I can tell by your avatar you know math.

So the number is 252 huh. Would still be profitable, but could never place 252 would take forever

**FourLengthsClear** · 11-24-11, 02:42 PM

Originally posted by LVBOUND

Thanks as I can tell by your avatar you know math.

So the number is 252 huh. Would still be profitable, but could never place 252 would take forever

You could place it as a round-robin bet.

**LVBOUND** · 11-24-11, 02:43 PM

Is that what a round robin does? Never tried it. Would that work with 10 games in sets of 5

**FourLengthsClear** · 11-24-11, 02:55 PM

Originally posted by LVBOUND

Is that what a round robin does? Never tried it. Would that work with 10 games in sets of 5

It would vary from book to book.
All Euro books (pretty much) would accept this wager, for US facing books it varies quite a lot.